Solve for X: Log 1331 Log 11 = Logx

Solve for x: `("log"1331)/("log"11)` = logx

Sum

`("log"1331)/("log"11)` = logx

⇒ `("log"11^3)/("log"11)` = logx

⇒ `(3"log"11)/(log"11)` = logx
⇒ 3 = logx
⇒ 3log10 = logx ...(since log10 = 1)
⇒ log 10³ = logx
∴ x = 10³
= 1000.

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More About Logarithm

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Chapter 10: Logarithms - Exercise 10.2

Chapter 10 Logarithms
Exercise 10.2 | Q 8.7

If a² = log x, b³ = log y and 3a² - 2b³ = 6 log z, express y in terms of x and z .

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log ( x + 1) + log ( x - 1) = log 11 + 2 log 3

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log_ba =-log_ab

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