Solve for X: Log 1331 Log 11 = Logx - Mathematics

Solve for x: `("log"1331)/("log"11)` = logx

Sum

`("log"1331)/("log"11)` = logx

⇒ `("log"11^3)/("log"11)` = logx

⇒ `(3"log"11)/(log"11)` = logx
⇒ 3 = logx
⇒ 3log10 = logx ...(since log10 = 1)
⇒ log 10³ = logx
∴ x = 10³
= 1000.

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Chapter 10: Logarithms - Exercise 10.2

Chapter 10 Logarithms
Exercise 10.2 | Q 8.7

If log`( a - b )/2 = 1/2( log a + log b )`, Show that : a² + b² = 6ab.

If log_√27x = 2 `(2)/(3)` , find x.

Given log₁₀x = 2a and log₁₀y = `b/2`. Write 10^{2b + 1} in terms of y.

Solve : log₅( x + 1 ) - 1 = 1 + log₅( x - 1 ).

Given x = log₁₀12 , y = log₄ 2 x log₁₀9 and z = log₁₀0.4 , find :
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(ii) 13^{x - y - z}

Solve the following:
log (3 - x) - log (x - 3) = 1

Solve for x: `("log"27)/("log"243)` = x

If log ₃ m = x and log₃ n = y, write down
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If 2 log x + 1 = log 360, find: log (3 x² - 8)

If `"a" = "log""p"^2/"qr", "b" = "log""q"^2/"rp", "c" = "log""r"^2/"pq"`, find the value of a + b + c.