Solve for X: Log 1331 Log 11 = Logx

Solve for x: `("log"1331)/("log"11)` = logx

Sum

`("log"1331)/("log"11)` = logx

⇒ `("log"11^3)/("log"11)` = logx

⇒ `(3"log"11)/(log"11)` = logx
⇒ 3 = logx
⇒ 3log10 = logx ...(since log10 = 1)
⇒ log 10³ = logx
∴ x = 10³
= 1000.

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More About Logarithm

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Chapter 7: Logarithms - Exercise 10.2

Chapter 7 Logarithms
Exercise 10.2 | Q 8.7

If log`( a - b )/2 = 1/2( log a + log b )`, Show that : a² + b² = 6ab.

Find x, if : log_x (5x - 6) = 2

Show that : log_a m ÷ log_ab m + 1 + log _ab

If log₂(x + y) = log₃(x - y) = `log 25/log 0.2`, find the values of x and y.

Solve the following:
log 7 + log (3x - 2) = log (x + 3) + 1

Solve the following:
log ₄ x + log₄(x-6) = 2

Solve the following:
`log_2x + log_4x + log_16x = (21)/(4)`

Solve for x: `("log"81)/("log"9)` = x

If log ₃ m = x and log₃ n = y, write down
`3^(1-2y+3x)` in terms of m an n

If 2 log x + 1 = log 360, find: log (3 x² - 8)