Advertisements
Advertisements
प्रश्न
Solve for x: `("log"1331)/("log"11)` = logx
Advertisements
उत्तर
`("log"1331)/("log"11)` = logx
⇒ `("log"11^3)/("log"11)` = logx
⇒ `(3"log"11)/(log"11)` = logx
⇒ 3 = logx
⇒ 3log10 = logx ...(since log10 = 1)
⇒ log 103 = logx
∴ x = 103
= 1000.
APPEARS IN
संबंधित प्रश्न
Find x, if : logx (5x - 6) = 2
Solve for x, if : logx49 - logx7 + logx `1/343` + 2 = 0
Given x = log1012 , y = log4 2 x log109 and z = log100.4 , find :
(i) x - y - z
(ii) 13x - y - z
Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`
Solve the following:
`log_2x + log_4x + log_16x = (21)/(4)`
Solve for x: `("log"27)/("log"243)` = x
Solve for x: `("log"81)/("log"9)` = x
Solve for x: `("log"289)/("log"17)` = logx
If log x = a and log y = b, write down
102b in terms of y
If `"a" = "log""p"^2/"qr", "b" = "log""q"^2/"rp", "c" = "log""r"^2/"pq"`, find the value of a + b + c.
