Advertisements
Advertisements
प्रश्न
Evaluate: `(log_5 8)/(log_25 16 xx Log_100 10)`
Advertisements
उत्तर
`(log_5 8)/(log_25 16 xx log_100 10)`
= `( log_10 8/ log_10 5)/(log_10 16/log_10 25 xx log_10 10/ log_10 100)`
= `( log_10 2^3/ log_10 5)/(log_10 2^4/log_10 5^2 xx log_10 10/ log_10 10^2)`
= `log_10 2^3/log_10 5 xx log_10 5^2/ log_10 2^4 xx log_10 10^2/ log_10 10 `
= `[3log_10 2]/log_10 5 xx [2log_10 5]/ [4log_10 2] xx[2log_10 10]/ [log_10 10] `
= 3
APPEARS IN
संबंधित प्रश्न
If `3/2 log a + 2/3` log b - 1 = 0, find the value of a9.b4 .
Solve for x and y ; if x > 0 and y > 0 ; log xy = log `x/y` + 2 log 2 = 2.
Evaluate : log38 ÷ log916
Solve the following:
log(x2 + 36) - 2log x = 1
Solve the following:
log ( x + 1) + log ( x - 1) = log 11 + 2 log 3
Solve for x: log (x + 5) = 1
Solve for x: `("log"121)/("log"11)` = logx
If log 3 m = x and log 3 n = y, write down
32x-3 in terms of m
If 2 log x + 1 = log 360, find: log (3 x2 - 8)
Prove that `("log"_"p" x)/("log"_"pq" x)` = 1 + logp q
