Express Log103 + 1 in Terms of Log10x.

Express log₁₀3 + 1 in terms of log₁₀x.

योग

log₁₀3 + 1
= log₁₀ 3 + log₁₀ 10
= log₁₀ (3 x 10)
= log₁₀30.

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More About Logarithm

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अध्याय 10: Logarithms - Exercise 10.2

अध्याय 10 Logarithms
Exercise 10.2 | Q 9

If a² + b² = 23ab, show that:

log `(a + b)/5 = 1/2`(log a + log b).

Show that : log_a m ÷ log_ab m + 1 + log _ab

If log₂(x + y) = log₃(x - y) = `log 25/log 0.2`, find the values of x and y.

Given log₁₀x = 2a and log₁₀y = `b/2`. Write 10^a in terms of x.

Evaluate : log₃8 ÷ log₉16

Solve the following:
`log_2x + log_4x + log_16x = (21)/(4)`

Solve for x: `("log"289)/("log"17)` = logx

State, true of false:

If `("log"49)/("log"7)` = log y, then y = 100.

Express the following in a form free from logarithm:
2 log x + 3 log y = log a

Prove that `("log"_"p" x)/("log"_"pq" x)` = 1 + log_p q