Express Log103 + 1 in Terms of Log10x.

Express log₁₀3 + 1 in terms of log₁₀x.

योग

log₁₀3 + 1
= log₁₀ 3 + log₁₀ 10
= log₁₀ (3 x 10)
= log₁₀30.

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More About Logarithm

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अध्याय 7: Logarithms - Exercise 10.2

अध्याय 7 Logarithms
Exercise 10.2 | Q 9

If a² = log x, b³ = log y and 3a² - 2b³ = 6 log z, express y in terms of x and z .

Find x, if : log_x (5x - 6) = 2

Evaluate: log_ba × log_c b × log_a c.

Given log₁₀x = 2a and log₁₀y = `b/2. "If" log_10^p = 3a - 2b`, express P in terms of x and y.

Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.

Solve the following:
log (3 - x) - log (x - 3) = 1

Solve the following:
log ( x + 1) + log ( x - 1) = log 11 + 2 log 3

If log x = a and log y = b, write down
10^2b in terms of y

Prove that `("log"_"p" x)/("log"_"pq" x)` = 1 + log_p q

Prove that: `(1)/("log"_2 30) + (1)/("log"_3 30) + (1)/("log"_5 30)` = 1