Express Log103 + 1 in Terms of Log10x.

Express log₁₀3 + 1 in terms of log₁₀x.

बेरीज

log₁₀3 + 1
= log₁₀ 3 + log₁₀ 10
= log₁₀ (3 x 10)
= log₁₀30.

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More About Logarithm

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पाठ 10: Logarithms - Exercise 10.2

पाठ 10 Logarithms
Exercise 10.2 | Q 9

If x = 1 + log 2 - log 5, y = 2 log3 and z = log a - log 5; find the value of a if x + y = 2z.

If a² = log x, b³ = log y and 3a² - 2b³ = 6 log z, express y in terms of x and z .

Given log₁₀x = 2a and log₁₀y = `b/2`. Write 10^a in terms of x.

Solve for x, if : log_x49 - log_x7 + log_x`1/343` + 2 = 0

Given x = log₁₀12 , y = log₄ 2 x log₁₀9 and z = log₁₀0.4 , find :
(i) x - y - z
(ii) 13^{x - y - z}

Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`

Solve the following:
log ₄ x + log₄(x-6) = 2

Solve for x: log (x + 5) = 1

If `"log" x^2 - "log"sqrt(y)` = 1, express y in terms of x. Hence find y when x = 2.

If x + log 4 + 2 log 5 + 3 log 3 + 2 log 2 = log 108, find the value of x.