Advertisements
Advertisements
प्रश्न
If x + log 4 + 2 log 5 + 3 log 3 + 2 log 2 = log 108, find the value of x.
Advertisements
उत्तर
x + log 4 + 2 log 5 + 3 log 3 + 2 log 2 = log 108
⇒ x = log 108 - log 4 - 2 log 5 - 3 log 3 - 2 log 2
= log (22 . 33) - log 22 - log 52 - log 33 - log 22
= `"log"((2^2. 3^3)/(2^2 . 5^2 . 3^3. 2^2))`
= `"log"(1/100)`
⇒ x
= log 1 - log 100
= 0 - 2
= -2
∴ x = -2.
APPEARS IN
संबंधित प्रश्न
If `3/2 log a + 2/3` log b - 1 = 0, find the value of a9.b4 .
Find x, if : logx 625 = - 4
Given x = log1012 , y = log4 2 x log109 and z = log100.4 , find :
(i) x - y - z
(ii) 13x - y - z
Solve the following:
log 8 (x2 - 1) - log 8 (3x + 9) = 0
Solve for x: log (x + 5) = 1
Solve for x: `("log"81)/("log"9)` = x
Find x and y, if `("log"x)/("log"5) = ("log"36)/("log"6) = ("log"64)/("log"y)`
If 2 log x + 1 = log 360, find: log(2 x -2)
Express the following in a form free from logarithm:
5 log m - 1 = 3 log n
Prove that log 10 125 = 3 (1 - log 10 2)
