Advertisements
Advertisements
प्रश्न
If a = log 20 b = log 25 and 2 log (p - 4) = 2a - b, find the value of 'p'.
Advertisements
उत्तर
a = log 20, b = log 25 and 2 log (p - 4) = 2a - b
⇒ 2 log (p - 4) = 2a - b
⇒ 2 log (p - 4) = 2log20 - log25
⇒ log (p - 4)2 = log202 - log25
⇒ log (p - 4)2 = `"log"(400/25)`
⇒ (p - 4)2 = `(400)/(25)`
⇒ p2 - 8p + 16 = 16
⇒ p2 - 8p = 0
⇒ p(p - 8) = 0
⇒ p = 0 or p = 8.
APPEARS IN
संबंधित प्रश्न
If m = log 20 and n = log 25, find the value of x, so that :
2 log (x - 4) = 2 m - n.
Evaluate: logb a × logc b × loga c.
Solve for x: `("log"27)/("log"243)` = x
Solve for x: `("log"125)/("log"5)` = logx
Solve for x: `("log"1331)/("log"11)` = logx
Find x and y, if `("log"x)/("log"5) = ("log"36)/("log"6) = ("log"64)/("log"y)`
If x + log 4 + 2 log 5 + 3 log 3 + 2 log 2 = log 108, find the value of x.
If a = `"log" 3/5, "b" = "log" 5/4 and "c" = 2 "log" sqrt(3/4`, prove that 5a+b-c = 1
If a b + b log a - 1 = 0, then prove that ba.ab = 10
Prove that: `(1)/("log"_2 30) + (1)/("log"_3 30) + (1)/("log"_5 30)` = 1
