Advertisements
Advertisements
प्रश्न
If a = log 20 b = log 25 and 2 log (p - 4) = 2a - b, find the value of 'p'.
Advertisements
उत्तर
a = log 20, b = log 25 and 2 log (p - 4) = 2a - b
⇒ 2 log (p - 4) = 2a - b
⇒ 2 log (p - 4) = 2log20 - log25
⇒ log (p - 4)2 = log202 - log25
⇒ log (p - 4)2 = `"log"(400/25)`
⇒ (p - 4)2 = `(400)/(25)`
⇒ p2 - 8p + 16 = 16
⇒ p2 - 8p = 0
⇒ p(p - 8) = 0
⇒ p = 0 or p = 8.
APPEARS IN
संबंधित प्रश्न
If a2 + b2 = 23ab, show that:
log `(a + b)/5 = 1/2`(log a + log b).
Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).
Solve the following:
log 8 (x2 - 1) - log 8 (3x + 9) = 0
Solve for x: `("log"81)/("log"9)` = x
State, true of false:
logba =-logab
If x + log 4 + 2 log 5 + 3 log 3 + 2 log 2 = log 108, find the value of x.
Prove that (log a)2 - (log b)2 = `"log"("a"/"b")."log"("ab")`
Prove that `("log"_"p" x)/("log"_"pq" x)` = 1 + logp q
Prove that: `(1)/("log"_2 30) + (1)/("log"_3 30) + (1)/("log"_5 30)` = 1
If `"a" = "log""p"^2/"qr", "b" = "log""q"^2/"rp", "c" = "log""r"^2/"pq"`, find the value of a + b + c.
