Advertisements
Advertisements
प्रश्न
Solve the following:
log ( x + 1) + log ( x - 1) = log 11 + 2 log 3
Advertisements
उत्तर
log ( x + 1) + log ( x - 1) = log 11 + 2 log 3
⇒ log [(x + 1)(x - 1)] = log 11 + log 32
⇒ log {x2 - 1} = log (11.9)
⇒ log {x2 - 1} = log99
⇒ x2 - 1 = 99
⇒ x2 = 100
So, x = 10 or -10
Negative value is rejected
So, x = 10.
APPEARS IN
संबंधित प्रश्न
Find x, if : logx 625 = - 4
Find x, if : logx (5x - 6) = 2
If log2(x + y) = log3(x - y) = `log 25/log 0.2`, find the values of x and y.
Given : `log x/ log y = 3/2` and log (xy) = 5; find the value of x and y.
Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.
Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`
Solve the following:
log(x2 + 36) - 2log x = 1
Solve the following:
`log_2x + log_4x + log_16x = (21)/(4)`
Express the following in a form free from logarithm:
5 log m - 1 = 3 log n
Prove that log 10 125 = 3 (1 - log 10 2)
