Given Log10x = 2a and Log10y = B/2. Write 102b + 1 In Terms of Y.

Given log₁₀x = 2a and log₁₀y = `b/2`. Write 10^{2b + 1} in terms of y.

योग

log₁₀y = `b/2`
⇒ y = 10^b/2⇒ y^{4 =}10^2b⇒ 10y⁴ = 10^2b x 10
⇒ 10^{2b + 1} = 10y⁴

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