Advertisements
Advertisements
प्रश्न
Express the following in a form free from logarithm:
m log x - n log y = 2 log 5
Advertisements
उत्तर
m log x - n log y = 2 log 5
⇒ log xm - log yn = log 52
⇒ `"log"(x^"m"/y^"n")` = log 52
⇒ `(x^"m"/y^"n")` = 52 = 25
⇒ xm = 25 yn.
APPEARS IN
संबंधित प्रश्न
If `3/2 log a + 2/3` log b - 1 = 0, find the value of a9.b4 .
If a2 + b2 = 23ab, show that:
log `(a + b)/5 = 1/2`(log a + log b).
Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).
Solve the following:
`log_2x + log_4x + log_16x = (21)/(4)`
Solve for x: `("log"121)/("log"11)` = logx
If log x = a and log y = b, write down
102b in terms of y
If x + log 4 + 2 log 5 + 3 log 3 + 2 log 2 = log 108, find the value of x.
Express the following in a form free from logarithm:
5 log m - 1 = 3 log n
Prove that log 10 125 = 3 (1 - log 10 2)
If a = log 20 b = log 25 and 2 log (p - 4) = 2a - b, find the value of 'p'.
