Advertisements
Advertisements
प्रश्न
Express the following in a form free from logarithm:
2 log x + 3 log y = log a
Advertisements
उत्तर
2 log x + 3 log y = log a
⇒ log x2 + log y3 = log a
⇒ log (x2 . y2) = log a
⇒ x2y3 = a.
APPEARS IN
संबंधित प्रश्न
Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
If x = log 0.6; y = log 1.25 and z = log 3 - 2 log 2, find the values of :
(i) x+y- z
(ii) 5x + y - z
If log2(x + y) = log3(x - y) = `log 25/log 0.2`, find the values of x and y.
Given : `log x/ log y = 3/2` and log (xy) = 5; find the value of x and y.
Solve the following:
log(x2 + 36) - 2log x = 1
Solve the following:
log 8 (x2 - 1) - log 8 (3x + 9) = 0
Solve for x: `("log"121)/("log"11)` = logx
If a = `"log" 3/5, "b" = "log" 5/4 and "c" = 2 "log" sqrt(3/4`, prove that 5a+b-c = 1
Express the following in a form free from logarithm:
`2"log" x + 1/2"log" y` = 1
Prove that log (1 + 2 + 3) = log 1 + log 2 + log 3. Is it true for any three numbers x, y, z?
