Advertisements
Advertisements
प्रश्न
Express the following in a form free from logarithm:
2 log x + 3 log y = log a
Advertisements
उत्तर
2 log x + 3 log y = log a
⇒ log x2 + log y3 = log a
⇒ log (x2 . y2) = log a
⇒ x2y3 = a.
APPEARS IN
संबंधित प्रश्न
Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
If x = log 0.6; y = log 1.25 and z = log 3 - 2 log 2, find the values of :
(i) x+y- z
(ii) 5x + y - z
If log√27x = 2 `(2)/(3)` , find x.
Find x, if : logx (5x - 6) = 2
Solve for x, if : logx49 - logx7 + logx `1/343` + 2 = 0
Solve the following:
log 7 + log (3x - 2) = log (x + 3) + 1
Solve the following:
log 8 (x2 - 1) - log 8 (3x + 9) = 0
If log 3 m = x and log 3 n = y, write down
32x-3 in terms of m
If a = `"log" 3/5, "b" = "log" 5/4 and "c" = 2 "log" sqrt(3/4`, prove that 5a+b-c = 1
If `"a" = "log""p"^2/"qr", "b" = "log""q"^2/"rp", "c" = "log""r"^2/"pq"`, find the value of a + b + c.
