Question

Given log₁₀x = 2a and log₁₀y = `b/2`. Write 10^{2b + 1} in terms of y.

Answer 1

log₁₀y = `b/2`
⇒ y = 10^b/2
⇒ y^{4 =} 10^2b
⇒ 10y⁴ = 10^2b x 10 
⇒ 10^{2b + 1} = 10y⁴