Advertisements
Advertisements
प्रश्न
Solve the following:
log 7 + log (3x - 2) = log (x + 3) + 1
Advertisements
उत्तर
log 7 + log (3x - 2) = log (x + 3) + 1
⇒ log 7 + log (3x - 2) - log (x + 3) = 1
⇒ `"log"(7.(3x - 2))/(x + 3)` = log 10
⇒ `(7.(3x - 2))/(x + 3)` = 10
⇒ 21x - 14 = 10(x + 3)
⇒ 21x - 10x = 30 + 14
⇒ 11x = 44
⇒ x = 44 / 11 = 4.
APPEARS IN
संबंधित प्रश्न
Given x = log1012 , y = log4 2 x log109 and z = log100.4 , find :
(i) x - y - z
(ii) 13x - y - z
Evaluate: `(log_5 8)/(log_25 16 xx Log_100 10)`
Solve the following:
log 4 x + log 4 (x-6) = 2
Solve for x: `("log"81)/("log"9)` = x
Solve for x: `("log"289)/("log"17)` = logx
Find x and y, if `("log"x)/("log"5) = ("log"36)/("log"6) = ("log"64)/("log"y)`
If 2 log x + 1 = log 360, find: log (3 x2 - 8)
Express the following in a form free from logarithm:
5 log m - 1 = 3 log n
Prove that log (1 + 2 + 3) = log 1 + log 2 + log 3. Is it true for any three numbers x, y, z?
Prove that: `(1)/("log"_2 30) + (1)/("log"_3 30) + (1)/("log"_5 30)` = 1
