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Question
Solve the following:
log 7 + log (3x - 2) = log (x + 3) + 1
Sum
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Solution
log 7 + log (3x - 2) = log (x + 3) + 1
⇒ log 7 + log (3x - 2) - log (x + 3) = 1
⇒ `"log"(7.(3x - 2))/(x + 3)` = log 10
⇒ `(7.(3x - 2))/(x + 3)` = 10
⇒ 21x - 14 = 10(x + 3)
⇒ 21x - 10x = 30 + 14
⇒ 11x = 44
⇒ x = 44 / 11 = 4.
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