Advertisements
Advertisements
प्रश्न
If log 3 m = x and log 3 n = y, write down
`3^(1-2y+3x)` in terms of m an n
Advertisements
उत्तर
`3^(1-2y+3x)` in terms of m an n
log 3 m = x
⇒ m = 3x
log 3 n = y
⇒ n = 3y
∴ `3^(1-2y+3x)`
= 3.3-2y.33x
= 3.(3y)-2.(3x)3
= 3n-2.m3
= `(3"m"^3)/"n"^2`.
APPEARS IN
संबंधित प्रश्न
If x = 1 + log 2 - log 5, y = 2 log3 and z = log a - log 5; find the value of a if x + y = 2z.
If x = log 0.6; y = log 1.25 and z = log 3 - 2 log 2, find the values of :
(i) x+y- z
(ii) 5x + y - z
If log2(x + y) = log3(x - y) = `log 25/log 0.2`, find the values of x and y.
Given log10x = 2a and log10y = `b/2`. Write 10a in terms of x.
Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`
Solve the following:
`log_2x + log_4x + log_16x = (21)/(4)`
Solve for x: `("log"128)/("log"32)` = x
If log x = a and log y = b, write down
10a-1 in terms of x
If log x = a and log y = b, write down
102b in terms of y
Prove that log 10 125 = 3 (1 - log 10 2)
