Advertisements
Advertisements
Question
If log 3 m = x and log 3 n = y, write down
`3^(1-2y+3x)` in terms of m an n
Advertisements
Solution
`3^(1-2y+3x)` in terms of m an n
log 3 m = x
⇒ m = 3x
log 3 n = y
⇒ n = 3y
∴ `3^(1-2y+3x)`
= 3.3-2y.33x
= 3.(3y)-2.(3x)3
= 3n-2.m3
= `(3"m"^3)/"n"^2`.
APPEARS IN
RELATED QUESTIONS
If a2 = log x, b3 = log y and 3a2 - 2b3 = 6 log z, express y in terms of x and z .
Find x, if : logx 625 = - 4
Show that : loga m ÷ logab m + 1 + log ab
Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).
Solve the following:
log 8 (x2 - 1) - log 8 (3x + 9) = 0
Solve for x: `("log"125)/("log"5)` = logx
Express the following in a form free from logarithm:
`2"log" x + 1/2"log" y` = 1
Express the following in a form free from logarithm:
5 log m - 1 = 3 log n
Prove that `("log"_"p" x)/("log"_"pq" x)` = 1 + logp q
If a = log 20 b = log 25 and 2 log (p - 4) = 2a - b, find the value of 'p'.
