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Question
Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
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Solution
⇒ `1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
⇒`1/( log_a bc + log_a a) + 1/(log_b ca +log_b b) + 1/ ( log_c ab + log_c c )`
⇒ `1/( log_a abc ) + 1/(log_b abc) + 1/ ( log_c abc )` ...[∵ loga b + loga c = loga bc ]
⇒ `(1) /[( log abc ) / ( loga )]` + `(1) /[( log abc ) / ( logb )]` + `(1) /[( log abc ) / ( logc )]`
⇒ ` ( log a + log b + log c) / ( log abc) `
⇒ `( log abc) / ( log abc) ` ...∵[ loga b + loga c = loga bc ]
⇒ 1
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