Advertisements
Advertisements
Question
If 2 log x + 1 = log 360, find: x
Advertisements
Solution
x
2logx + 1 = log360
⇒ logx2 + log10 = log360
⇒ log(10x2) = log360
⇒ 10x2 = 360
⇒ x2 = `(360)/(10)` = 36
⇒ x = `sqrt(36)` = ±6
As negative value is rejected,
∴ x = 6.
APPEARS IN
RELATED QUESTIONS
If x = 1 + log 2 - log 5, y = 2 log3 and z = log a - log 5; find the value of a if x + y = 2z.
If log`( a - b )/2 = 1/2( log a + log b )`, Show that : a2 + b2 = 6ab.
If log2(x + y) = log3(x - y) = `log 25/log 0.2`, find the values of x and y.
Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.
Solve the following:
log(x2 + 36) - 2log x = 1
Solve for x: `("log"121)/("log"11)` = logx
Solve for x: `("log"128)/("log"32)` = x
If `"log" x^2 - "log"sqrt(y)` = 1, express y in terms of x. Hence find y when x = 2.
Prove that (log a)2 - (log b)2 = `"log"("a"/"b")."log"("ab")`
If `"a" = "log""p"^2/"qr", "b" = "log""q"^2/"rp", "c" = "log""r"^2/"pq"`, find the value of a + b + c.
