Advertisements
Advertisements
प्रश्न
Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
Advertisements
उत्तर
⇒ `1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
⇒`1/( log_a bc + log_a a) + 1/(log_b ca +log_b b) + 1/ ( log_c ab + log_c c )`
⇒ `1/( log_a abc ) + 1/(log_b abc) + 1/ ( log_c abc )` ...[∵ loga b + loga c = loga bc ]
⇒ `(1) /[( log abc ) / ( loga )]` + `(1) /[( log abc ) / ( logb )]` + `(1) /[( log abc ) / ( logc )]`
⇒ ` ( log a + log b + log c) / ( log abc) `
⇒ `( log abc) / ( log abc) ` ...∵[ loga b + loga c = loga bc ]
⇒ 1
APPEARS IN
संबंधित प्रश्न
Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`
Solve the following:
log(x2 + 36) - 2log x = 1
Solve for x: `("log"128)/("log"32)` = x
If 2 log x + 1 = log 360, find: x
If 2 log x + 1 = log 360, find: log (3 x2 - 8)
If x + log 4 + 2 log 5 + 3 log 3 + 2 log 2 = log 108, find the value of x.
If a = `"log" 3/5, "b" = "log" 5/4 and "c" = 2 "log" sqrt(3/4`, prove that 5a+b-c = 1
Express the following in a form free from logarithm:
`2"log" x + 1/2"log" y` = 1
If a b + b log a - 1 = 0, then prove that ba.ab = 10
If `"a" = "log""p"^2/"qr", "b" = "log""q"^2/"rp", "c" = "log""r"^2/"pq"`, find the value of a + b + c.
