Solve for x: log⁡125log⁡5 = logx

Solve for x: `("log"125)/("log"5)` = logx

Sum

`("log"125)/("log"5)` = logx

⇒ `("log"5^3)/("log"5)` = logx

⇒ `(3"log"5)/("log"5)` = logx
⇒ 3 = logx
⇒ 3log10 = log x ...(since log 10 = 1)
⇒ log 10³ = logx
∴ x = 10³
= 1000

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More About Logarithm

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Chapter 7: Logarithms - Exercise 10.2

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