Question

Solve for x: `("log"121)/("log"11)` = logx

Answer 1

`("log"121)/("log"11)` = logx

⇒ `("log"11^2)/("lo"11)` = logx

⇒ `(2"log"11)/("log"11)` = logx
= 2 = logx
⇒  2log 10 = logx   ...(since log 10 = 1)
⇒  log 10² = logx
∴ x = 10²
= 100.