Advertisements
Advertisements
प्रश्न
Solve for x: `("log"121)/("log"11)` = logx
Advertisements
उत्तर
`("log"121)/("log"11)` = logx
⇒ `("log"11^2)/("lo"11)` = logx
⇒ `(2"log"11)/("log"11)` = logx
= 2 = logx
⇒ 2log 10 = logx ...(since log 10 = 1)
⇒ log 102 = logx
∴ x = 102
= 100.
APPEARS IN
संबंधित प्रश्न
If log`( a - b )/2 = 1/2( log a + log b )`, Show that : a2 + b2 = 6ab.
Solve for x and y ; if x > 0 and y > 0 ; log xy = log `x/y` + 2 log 2 = 2.
If p = log 20 and q = log 25 , find the value of x , if 2log( x + 1 ) = 2p - q.
Given log10x = 2a and log10y = `b/2`. Write 10a in terms of x.
Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`
Evaluate: `(log_5 8)/(log_25 16 xx Log_100 10)`
Express log103 + 1 in terms of log10x.
State, true of false:
logba =-logab
If a b + b log a - 1 = 0, then prove that ba.ab = 10
Prove that log 10 125 = 3 (1 - log 10 2)
