Question

If a   b + b log  a - 1 = 0, then prove that b^a.a^b = 10

Answer 1

Given alogb + bloga - 1 = 0
⇒ log(b)^a + log(a)^b - log10 = 0
⇒ log(b^a . a^b) = log 10
∴ b^a . a^b = 10.