If a B + B Log a - 1 = 0, Then Prove that Ba.Ab = 10

If a b + b log a - 1 = 0, then prove that b^a.a^b = 10

Sum

Given alogb + bloga - 1 = 0
⇒ log(b)^a + log(a)^b- log10 = 0
⇒ log(b^a . a^b) = log 10
∴ b^a . a^b = 10.

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