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Question
If log (a + 1) = log (4a - 3) - log 3; find a.
Sum
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Solution
log (a + 1) = log (4a - 3) - log 3
⇒ log (a + 1) + log 3 = log (4a - 3)
⇒ log {3(a + 1)} = log (4a - 3)
⇒ 3 (a + 1) = 4a - 3
⇒ 3a + 3 = 4a - 3
⇒ 4a - 3a = 3 + 3
⇒ a = 6.
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