Advertisements
Advertisements
प्रश्न
Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.
Advertisements
उत्तर
logx15√5 = 2 - logx3√5
⇒ logx15√5 + logx3√5 = 2
⇒ logx( 15√5 x 3√5 ) = 2
⇒ logx 225 = 2
⇒ logx 152 = 2
⇒ 2logx 15 = 2
⇒ logx15 = 1
⇒ x = 15.
APPEARS IN
संबंधित प्रश्न
Given log10x = 2a and log10y = `b/2`. Write 10a in terms of x.
Given log10x = 2a and log10y = `b/2. "If" log_10^p = 3a - 2b`, express P in terms of x and y.
Solve the following:
log 8 (x2 - 1) - log 8 (3x + 9) = 0
Solve the following:
log (x + 1) + log (x - 1) = log 48
If 2 log x + 1 = log 360, find: x
If 2 log x + 1 = log 360, find: log (3 x2 - 8)
Prove that (log a)2 - (log b)2 = `"log"("a"/"b")."log"("ab")`
If a b + b log a - 1 = 0, then prove that ba.ab = 10
Prove that log 10 125 = 3 (1 - log 10 2)
If a = log 20 b = log 25 and 2 log (p - 4) = 2a - b, find the value of 'p'.
