Advertisements
Advertisements
प्रश्न
Prove that (log a)2 - (log b)2 = `"log"("a"/"b")."log"("ab")`
Advertisements
उत्तर
L.H.S.
= (log a)2 - (log b)2
= (log a + log b)(log a - log b) ...{using identity m2 - n2 = (m + n)(m - n)}
= `"log"("ab")"log"("a"/"b")`
= `"log"("a"/"b")."log"("ab")`
= R.H.S.
APPEARS IN
संबंधित प्रश्न
Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
Evaluate: logb a × logc b × loga c.
Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).
Solve the following:
log(x2 + 36) - 2log x = 1
Solve for x: `("log"125)/("log"5)` = logx
Express log103 + 1 in terms of log10x.
If 2 log x + 1 = log 360, find: log (3 x2 - 8)
If a = `"log" 3/5, "b" = "log" 5/4 and "c" = 2 "log" sqrt(3/4`, prove that 5a+b-c = 1
Express the following in a form free from logarithm:
`2"log" x + 1/2"log" y` = 1
Express the following in a form free from logarithm:
5 log m - 1 = 3 log n
