Advertisements
Advertisements
प्रश्न
Prove that log (1 + 2 + 3) = log 1 + log 2 + log 3. Is it true for any three numbers x, y, z?
Advertisements
उत्तर
log (1 + 2 + 3) = log 6
= log (1 + 2 + 3) = log 1 + log 2 + log 3
No, this property is not true for any numbers x, y, z
For example, log (1 + 3 + 5) = log 9
log 1 + log 3 + log 5 = log (1 x 3 x 5) = log 15
log (1 + 3 + 5) ≠ log 1 + log 3 + log 5.
APPEARS IN
संबंधित प्रश्न
If log`( a - b )/2 = 1/2( log a + log b )`, Show that : a2 + b2 = 6ab.
If a2 + b2 = 23ab, show that:
log `(a + b)/5 = 1/2`(log a + log b).
Find x, if : logx 625 = - 4
Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`
Solve for x: log (x + 5) = 1
Find x and y, if `("log"x)/("log"5) = ("log"36)/("log"6) = ("log"64)/("log"y)`
If `"log" x^2 - "log"sqrt(y)` = 1, express y in terms of x. Hence find y when x = 2.
If 2 log x + 1 = log 360, find: log (3 x2 - 8)
Express the following in a form free from logarithm:
2 log x + 3 log y = log a
If log (a + 1) = log (4a - 3) - log 3; find a.
