Advertisements
Advertisements
प्रश्न
Solve for x, if : logx49 - logx7 + logx `1/343` + 2 = 0
Advertisements
उत्तर
logx49 - logx7 + logx `1/343` + 2 = 0
⇒ logx49 - logx7 + logx (343)-1 = - 2
⇒ logx49 - logx7 - logx (343) = - 2
⇒ logx`[49/[7 xx 343]]` = - 2
⇒ logx`[1/49]` = - 2
⇒ x-2 = `1/49`
⇒ `1/x^2=1/49`
⇒ x2 = 49
⇒ x = `sqrt49`
⇒ x = 7
APPEARS IN
संबंधित प्रश्न
If a2 + b2 = 23ab, show that:
log `(a + b)/5 = 1/2`(log a + log b).
Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).
Evaluate : log38 ÷ log916
Evaluate: `(log_5 8)/(log_25 16 xx Log_100 10)`
Solve the following:
log 4 x + log 4 (x-6) = 2
Solve for x: `("log"81)/("log"9)` = x
If a = `"log" 3/5, "b" = "log" 5/4 and "c" = 2 "log" sqrt(3/4`, prove that 5a+b-c = 1
Express the following in a form free from logarithm:
`2"log" x + 1/2"log" y` = 1
Express the following in a form free from logarithm:
5 log m - 1 = 3 log n
If log (a + 1) = log (4a - 3) - log 3; find a.
