Advertisements
Advertisements
प्रश्न
Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).
Advertisements
उत्तर
log5( x + 1 ) - 1 = 1 + log5( x - 1 )
⇒ log5( x + 1 ) - log5( x - 1 ) = 2
⇒ `log_5 ( x + 1 )/( x - 1 ) = 2`
⇒ `( x + 1 )/( x - 1 ) = 5^2`
⇒ `( x + 1 )/( x - 1 ) = 25`
⇒ x + 1 = 25( x - 1 )
⇒ x + 1 = 25x - 25
⇒ 25x - x = 25 + 1
⇒ 24x = 26
⇒ x = `26/24 = 13/12`.
APPEARS IN
संबंधित प्रश्न
If log`( a - b )/2 = 1/2( log a + log b )`, Show that : a2 + b2 = 6ab.
If a2 + b2 = 23ab, show that:
log `(a + b)/5 = 1/2`(log a + log b).
Given x = log1012 , y = log4 2 x log109 and z = log100.4 , find :
(i) x - y - z
(ii) 13x - y - z
Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.
Solve the following:
log ( x + 1) + log ( x - 1) = log 11 + 2 log 3
Solve the following:
log 4 x + log 4 (x-6) = 2
Solve for x: `("log"27)/("log"243)` = x
Express log103 + 1 in terms of log10x.
If log x = a and log y = b, write down
10a-1 in terms of x
If 2 log x + 1 = log 360, find: log(2 x -2)
