Advertisements
Advertisements
प्रश्न
Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).
Advertisements
उत्तर
log5( x + 1 ) - 1 = 1 + log5( x - 1 )
⇒ log5( x + 1 ) - log5( x - 1 ) = 2
⇒ `log_5 ( x + 1 )/( x - 1 ) = 2`
⇒ `( x + 1 )/( x - 1 ) = 5^2`
⇒ `( x + 1 )/( x - 1 ) = 25`
⇒ x + 1 = 25( x - 1 )
⇒ x + 1 = 25x - 25
⇒ 25x - x = 25 + 1
⇒ 24x = 26
⇒ x = `26/24 = 13/12`.
APPEARS IN
संबंधित प्रश्न
Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
If a2 + b2 = 23ab, show that:
log `(a + b)/5 = 1/2`(log a + log b).
Find x, if : logx 625 = - 4
Given log10x = 2a and log10y = `b/2`. Write 10a in terms of x.
Given log10x = 2a and log10y = `b/2`. Write 102b + 1 in terms of y.
Solve the following:
log(x2 + 36) - 2log x = 1
Solve the following:
log (x + 1) + log (x - 1) = log 48
Solve for x: `("log"1331)/("log"11)` = logx
If log 3 m = x and log 3 n = y, write down
`3^(1-2y+3x)` in terms of m an n
Find x and y, if `("log"x)/("log"5) = ("log"36)/("log"6) = ("log"64)/("log"y)`
