Advertisements
Advertisements
प्रश्न
Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.
Advertisements
उत्तर
logx15√5 = 2 - logx3√5
⇒ logx15√5 + logx3√5 = 2
⇒ logx( 15√5 x 3√5 ) = 2
⇒ logx 225 = 2
⇒ logx 152 = 2
⇒ 2logx 15 = 2
⇒ logx15 = 1
⇒ x = 15.
APPEARS IN
संबंधित प्रश्न
If x = 1 + log 2 - log 5, y = 2 log3 and z = log a - log 5; find the value of a if x + y = 2z.
If p = log 20 and q = log 25 , find the value of x , if 2log( x + 1 ) = 2p - q.
Evaluate: logb a × logc b × loga c.
Given log10x = 2a and log10y = `b/2. "If" log_10^p = 3a - 2b`, express P in terms of x and y.
Solve the following:
log ( x + 1) + log ( x - 1) = log 11 + 2 log 3
Solve the following:
log (x + 1) + log (x - 1) = log 48
Solve for x: `("log"121)/("log"11)` = logx
State, true of false:
logba =-logab
If x + log 4 + 2 log 5 + 3 log 3 + 2 log 2 = log 108, find the value of x.
If `"a" = "log""p"^2/"qr", "b" = "log""q"^2/"rp", "c" = "log""r"^2/"pq"`, find the value of a + b + c.
