Advertisements
Advertisements
प्रश्न
Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.
Advertisements
उत्तर
logx15√5 = 2 - logx3√5
⇒ logx15√5 + logx3√5 = 2
⇒ logx( 15√5 x 3√5 ) = 2
⇒ logx 225 = 2
⇒ logx 152 = 2
⇒ 2logx 15 = 2
⇒ logx15 = 1
⇒ x = 15.
APPEARS IN
संबंधित प्रश्न
If `3/2 log a + 2/3` log b - 1 = 0, find the value of a9.b4 .
Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
If x = log 0.6; y = log 1.25 and z = log 3 - 2 log 2, find the values of :
(i) x+y- z
(ii) 5x + y - z
Show that : loga m ÷ logab m + 1 + log ab
Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).
Solve the following:
log ( x + 1) + log ( x - 1) = log 11 + 2 log 3
Solve the following:
log (x + 1) + log (x - 1) = log 48
Solve for x: `("log"81)/("log"9)` = x
Find x and y, if `("log"x)/("log"5) = ("log"36)/("log"6) = ("log"64)/("log"y)`
If 2 log x + 1 = log 360, find: x
