Advertisements
Advertisements
प्रश्न
Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.
बेरीज
Advertisements
उत्तर
logx15√5 = 2 - logx3√5
⇒ logx15√5 + logx3√5 = 2
⇒ logx( 15√5 x 3√5 ) = 2
⇒ logx 225 = 2
⇒ logx 152 = 2
⇒ 2logx 15 = 2
⇒ logx15 = 1
⇒ x = 15.
shaalaa.com
More About Logarithm
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`
Given : `log x/ log y = 3/2` and log (xy) = 5; find the value of x and y.
Solve the following:
log (3 - x) - log (x - 3) = 1
Solve the following:
log 4 x + log 4 (x-6) = 2
Solve for x: log (x + 5) = 1
Solve for x: `("log"128)/("log"32)` = x
State, true of false:
If `("log"49)/("log"7)` = log y, then y = 100.
If 2 log x + 1 = log 360, find: x
If 2 log x + 1 = log 360, find: log(2 x -2)
If log (a + 1) = log (4a - 3) - log 3; find a.
