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Solve: 1 - x1 + xxtan-1(1 - x1 + x)=12(tan-1x), for x > 0. - Mathematics and Statistics

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Question

Solve: `tan^-1 ("1 - x"/"1 + x") = 1/2 (tan^-1 "x")`, for x > 0.

Sum
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Solution

`tan^-1 ("1 - x"/"1 + x") = 1/2 (tan^-1 "x")`

∴ `2 tan^-1 ("1 - x"/"1 + x") = (tan^-1 "x")`

∴ `tan^-1  [(2 ("1 - x"/"1 + x"))/(1 - ("1 - x"/"1 + x")^2)] = tan^-1 "x"   ....[because 2 tan^-1 "x" = tan^-1  (("2x")/(1- "x"^2))]`

∴ `(2 ("1 - x"/"1 + x")(1 + "x")^2)/((1 + "x")^2 - (1 - "x")^2) = "x"`

∴ `(2 (1 - "x")(1 + "x"))/((1 + "2x" + "x"^2) - (1 - "2x" + "x"^2)) = "x"`

∴ `(2(1 - "x"^2))/(1 + "2x" + "x"^2 - 1 + 2"x" - "x"^2) = "x"`

∴ `(2 - 2"x"^2)/"4x" = "x"`

∴ 2 - 2x2 = 4x2

∴ 6x2 = 2

∴ x2 = `1/3`

∴ x = `1/sqrt3`   .  ....[∵ x > 0]

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Chapter 3: Trigonometric Functions - Miscellaneous exercise 3 [Page 110]

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Balbharati Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 27 | Page 110

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