Advertisements
Advertisements
Question
Simplify:
`(27"x"^-3"y"^6)^(2/3)`
Sum
Advertisements
Solution
`(27"x"^-3"y"^6)^(2/3)=(27)^(2/3)."x"^(-3xx2/3)."y"^(6xx2/3`
`=(3xx3xx3)^(2/3)."x"^-2."y"^4`
`=[(3xx3xx3)^(1/3)]^2."x"^-2."y"^4`
`=3^2."x"^-2"y"^4`
`=9"x"^-2"y"^4`
`=(9"y"^4)/"x"^2=9"x"^-2"y"^4`
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`(4^7)^2xx(4^-3)^4`
Compute:
`(27/64)^(-2/3)`
Simplify:
`8^(4/3)+25^(3/2)-(1/27)^(-2/3)`
Simplify:
`(2^-3-2^-4)(2^-3+2^-4)`
Evaluate:
`(8+4+2)^0`
Evaluate:
`9^0+9^-1-9^-2+9^(1/2)-9^(-1/2)`
Simplify:
`5"z"^16÷15"z"^-11`
Simplify:
`(-2"x"^(2/3)"y"^(-3/2))^6`
Simplify and express as positive indice:
(xy)(m-n).(yz)(n-l).(zx)(l-m)
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
