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Question
Simplify:
`(2"x"^2"y"^-3)^-2`
Sum
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Solution
`(2"x"^2"y"^-3)^-2=2^-2."x"^(2xx-2)."y"^(-3xx-2)`
`=1/2^2"x"^-4."y"^6`
`=1/4xx"y"^6/"x"^4`
`="y"^6/(4"x"^4)=1/4."y"^6."x"^-4`
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