Advertisements
Advertisements
Question
Simplify:
`(2"x"^2"y"^-3)^-2`
Sum
Advertisements
Solution
`(2"x"^2"y"^-3)^-2=2^-2."x"^(2xx-2)."y"^(-3xx-2)`
`=1/2^2"x"^-4."y"^6`
`=1/4xx"y"^6/"x"^4`
`="y"^6/(4"x"^4)=1/4."y"^6."x"^-4`
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`1^8xx3^0xx5^3xx2^2`
Compute:
`(2/3)^(-4)xx(27/8)^-2`
Compute:
`(56/28)^0÷(2/5)^3xx16/25`
Compute:
`(27)^(2/3)÷(81/16)^(-1/4)`
Evaluate:
`(8+4+2)^0`
Simplify:
`"x"^10"y"^6÷"x"^3"y"^-2`
Simplify:
`(36"x"^2)^(1/2)`
Prove that:
`1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a"))=1`
Simplify:
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1)`
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
