Advertisements
Advertisements
Question
Evaluate:
`(8+4+2)^0`
Sum
Advertisements
Solution
`(8+4+2)^0=(14)^0=1` `(∵"a"^0=1)`
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`(4^7)^2xx(4^-3)^4`
Compute:
`(12)^-2xx3^3`
Compute:
`(27/64)^(-2/3)`
Simplify:
`(2^-3-2^-4)(2^-3+2^-4)`
Evaluate:
`4"x"^0`
Evaluate:
`[(10^3)^0]^5`
Evaluate:
`(7"x"^0)^2`
Simplify:
`("a"^5"b"^2)/("a"^2"b"^-3`
Show that:
`(("x"^"a")/"x"^(-"b"))^("a"-"b").(("x"^"b")/"x"^(-"c"))^("b"-"c").(("x"^"c")/("x"^(-"a")))^("c"-"a")=1`
Prove that:
`((x^a)/x^b)^(1/(ab))((x^b)/x^c)^(1/(bc))(x^c/x^a)^(1/(ca))=1`
