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Question
Simplify and express as positive indice:
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
Sum
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Solution
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
`=("a"^(-2xx1/2)."b"^(1/2))xx("a"^(1/3)"b"^(-3xx1/3))`
`="a"^-1"b"^(1/2)xx"a"^(1/3)"b"^-1`
`="a"^(-1+1/3)"b"^(1/2-1)`
`="a"^((-2)/3)"b"^((-1)/2)`
`=1/("a"^(2/3)"b"1/2)`
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