Advertisements
Advertisements
Question
Simplify and express as positive indice:
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
Sum
Advertisements
Solution
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
`=("a"^(-2xx1/2)."b"^(1/2))xx("a"^(1/3)"b"^(-3xx1/3))`
`="a"^-1"b"^(1/2)xx"a"^(1/3)"b"^-1`
`="a"^(-1+1/3)"b"^(1/2-1)`
`="a"^((-2)/3)"b"^((-1)/2)`
`=1/("a"^(2/3)"b"1/2)`
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`(27/64)^(-2/3)`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Compute:
`(27)^(2/3)÷(81/16)^(-1/4)`
Evaluate:
`8^0+4^0+2^0`
Evaluate:
`(7"x"^0)^2`
Simplify:
`(36"x"^2)^(1/2)`
Evaluate:
`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`
Prove that:
`1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a"))=1`
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
