Advertisements
Advertisements
प्रश्न
Simplify and express as positive indice:
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
बेरीज
Advertisements
उत्तर
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
`=("a"^(-2xx1/2)."b"^(1/2))xx("a"^(1/3)"b"^(-3xx1/3))`
`="a"^-1"b"^(1/2)xx"a"^(1/3)"b"^-1`
`="a"^(-1+1/3)"b"^(1/2-1)`
`="a"^((-2)/3)"b"^((-1)/2)`
`=1/("a"^(2/3)"b"1/2)`
shaalaa.com
More About Exponents
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Compute:
`(2^-9÷2^-11)^3`
Compute:
`(2/3)^(-4)xx(27/8)^-2`
Compute:
`(-5)^4xx(-5)^6÷(-5)^9`
Compute:
`(27/64)^(-2/3)`
Compute:
`(-3)^4-(root(4)(3))^0xx(-2)^5÷(64)^(2/3)`
Evaluate:
`(-5)^0`
Evaluate:
`9^0+9^-1-9^-2+9^(1/2)-9^(-1/2)`
Simplify:
`(-2"x"^(2/3)"y"^(-3/2))^6`
Simplify and express as positive indice:
(xy)(m-n).(yz)(n-l).(zx)(l-m)
Find the value of n, when:
`12^-5xx12^(2"n"+1)=12^13÷12^7`
