Advertisements
Advertisements
प्रश्न
Simplify and express as positive indice:
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
बेरीज
Advertisements
उत्तर
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
`=("a"^(-2xx1/2)."b"^(1/2))xx("a"^(1/3)"b"^(-3xx1/3))`
`="a"^-1"b"^(1/2)xx"a"^(1/3)"b"^-1`
`="a"^(-1+1/3)"b"^(1/2-1)`
`="a"^((-2)/3)"b"^((-1)/2)`
`=1/("a"^(2/3)"b"1/2)`
shaalaa.com
More About Exponents
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Compute:
`(2/3)^(-4)xx(27/8)^-2`
Compute:
`(27)^(2/3)÷(81/16)^(-1/4)`
Evaluate:
`[(10^3)^0]^5`
Evaluate:
`(7"x"^0)^2`
Simplify:
`15"y"^8÷3"y"^3`
Simplify:
`(-2"x"^(2/3)"y"^(-3/2))^6`
Prove that:
`((x^a)/x^b)^(1/(ab))((x^b)/x^c)^(1/(bc))(x^c/x^a)^(1/(ca))=1`
Prove that:
`1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a"))=1`
Find the value of n, when:
`12^-5xx12^(2"n"+1)=12^13÷12^7`
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
