Advertisements
Advertisements
Question
Compute:
`(2^-9÷2^-11)^3`
Sum
Advertisements
Solution
`(2^-9÷2^-11)^3=(2^-9/2^-11)^3`
=`(2^(-9+11))^3`
=`(2^2)^3=2^6`
=`2xx2xx2xx2xx2xx2`
= 64
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`(56/28)^0÷(2/5)^3xx16/25`
Compute:
`(-3)^4-(root(4)(3))^0xx(-2)^5÷(64)^(2/3)`
Simplify:
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
Simplify:
`(2^-3-2^-4)(2^-3+2^-4)`
Evaluate:
`4"x"^0`
Evaluate:
`(7"x"^0)^2`
Simplify:
`(36"x"^2)^(1/2)`
Simplify:
`(125"x"^-3)^(1/3)`
Evaluate:
`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
