Advertisements
Advertisements
Question
Simplify:
`8^(4/3)+25^(3/2)-(1/27)^(-2/3)`
Sum
Advertisements
Solution
`8^(4/3)+25^(3/2)-(1/27)^(-2/3)`
`=(2^3)^(4/3)+(5^2)^(3/2)- (27)^(2/3)`
`=2^(3xx4/3)+5^(2xx3/2)-3^(3xx2/3)`
`=2^4+5^3-3^2`
`=16+125 - 9 = 132`
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`(27/64)^(-2/3)`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Compute:
`(27)^(2/3)÷(81/16)^(-1/4)`
Simplify:
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
Simplify:
`(36"x"^2)^(1/2)`
Evaluate:
`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`
Prove that:
`((x^a)/x^b)^(1/(ab))((x^b)/x^c)^(1/(bc))(x^c/x^a)^(1/(ca))=1`
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
