Advertisements
Advertisements
Question
Compute:
`(4^7)^2xx(4^-3)^4`
Sum
Advertisements
Solution
`(4^7)^2xx(4^-3)^4`
=`4^14xx4^-12`
=`4^(14-12)=4^2`
=`4xx4`
=16
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`(2/3)^(-4)xx(27/8)^-2`
Compute:
`(56/28)^0÷(2/5)^3xx16/25`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Evaluate:
`[(10^3)^0]^5`
Simplify:
`("a"^5"b"^2)/("a"^2"b"^-3`
Simplify:
`5"z"^16÷15"z"^-11`
Simplify:
`(125"x"^-3)^(1/3)`
Simplify and express as positive indice:
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
Simplify and express as positive indice:
(xy)(m-n).(yz)(n-l).(zx)(l-m)
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
