Advertisements
Advertisements
Question
Simplify:
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1)`
Advertisements
Solution
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1))`
Given expression`=("a"^(2"n"+3)."a"^((2"n"^2+4"n"+"n"+2)))/("a"^(6"n"+3)."a"^(2"n"^2+"n"`
`="a"^(2"n"+3+2"n"^2+5"n"+2)/"a"^(6"n"+3+2"n"^2+"n")`
`="a"^(2"n"^2+7"n"+5)/"a"^(2"n"^2+7"n"+3`
`= a^(2n^2 +7n + 5 - 2n^2 - 7n - 3 )`
`= a^2`
APPEARS IN
RELATED QUESTIONS
Compute:
`(4^7)^2xx(4^-3)^4`
Compute:
`(-5)^4xx(-5)^6÷(-5)^9`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`(125)^(-2/3)÷(8)^(2/3)`
Compute:
`(-3)^4-(root(4)(3))^0xx(-2)^5÷(64)^(2/3)`
Simplify:
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
Evaluate:
`8^0+4^0+2^0`
Evaluate:
`(8+4+2)^0`
Simplify:
`(-2"x"^(2/3)"y"^(-3/2))^6`
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
