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Question
Simplify:
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
Sum
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Solution
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
= `(2^6)^(-2xx-3) ÷ (-8)^(2xx3xx2)`
= `2^(6xx(6)) ÷ (-8)^12`
= `2^(+36)÷(-8)^12`
= `2^(+36)÷[(-2)^3]^12`
= `2^36÷(-2)^36`
= `2^36/(-2)^36`
= `2^36/2^36` ...(∵36 is even)
= `2^(36-36)`
= 20 ...(∵ a0 = 1)
= 1
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