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Question
Compute:
`(56/28)^0÷(2/5)^3xx16/25`
Sum
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Solution
`(56/28)^0÷(2/5)^3xx16/25`
=`1÷2^3/5^3xx(2xx2xx2xx2)/(5xx5)`
`[∵(56/28)^0=1]`
=`1xx5^3/2^3xx2^4/5^2=5^(3-2)xx2^(4-3)`
=`5^1xx2^1=10`
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