Advertisements
Advertisements
Question
Evaluate:
`(7"x"^0)^2`
One Line Answer
Advertisements
Solution
`(7"x"^0)^2=7^2xx"x"^(0xx2)=49xx1=49`
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`(4^7)^2xx(4^-3)^4`
Compute:
`(12)^-2xx3^3`
Compute:
`(-5)^4xx(-5)^6÷(-5)^9`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`(27/64)^(-2/3)`
Simplify:
`(2^-3-2^-4)(2^-3+2^-4)`
Evaluate:
`[(10^3)^0]^5`
Simplify:
`("a"^5"b"^2)/("a"^2"b"^-3`
Show that:
`(("x"^"a")/"x"^(-"b"))^("a"-"b").(("x"^"b")/"x"^(-"c"))^("b"-"c").(("x"^"c")/("x"^(-"a")))^("c"-"a")=1`
Prove that:
`1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a"))=1`
