Advertisements
Advertisements
Question
Evaluate:
`(7"x"^0)^2`
One Line Answer
Advertisements
Solution
`(7"x"^0)^2=7^2xx"x"^(0xx2)=49xx1=49`
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`1^8xx3^0xx5^3xx2^2`
Compute:
`(56/28)^0÷(2/5)^3xx16/25`
Compute:
`9^0xx4^-1÷2^-4`
Simplify:
`8^(4/3)+25^(3/2)-(1/27)^(-2/3)`
Simplify:
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
Evaluate:
`(8+4+2)^0`
Evaluate:
`4"x"^0`
Simplify:
`"x"^10"y"^6÷"x"^3"y"^-2`
Prove that:
`("m"+"n")^-1("m"^-1+"n"^-1)=("m""n")^-1`
Find the value of n, when:
`12^-5xx12^(2"n"+1)=12^13÷12^7`
