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Question
Prove that:
`("m"+"n")^-1("m"^-1+"n"^-1)=("m""n")^-1`
Theorem
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Solution
`"L"."H"."S". ("m"+"n")^-1("m"^-1+"n"^-1)`
= `1/("m"+"n")(1/"m"+1/"n")`
= `1/("m"+"n").("n"+"m")/("m""n")`
= `1/("m""n"`
= `("m""n")^-1`
= R.H.S.
Hence, proved.
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