Advertisements
Advertisements
Question
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
Sum
Advertisements
Solution
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
`("a"^(2"n"-3)xxa^(2"n"+2))/"a"^-12="a"^9÷"a"^-18`
`("a"^(2"n"-3)xx2^(2"n"+2))/"a"^-12="a"^9/"a"^-18`
`"a"^(2"n"-3+2"n"+2-(-12)="a"^9-(-18))`
`"a"^(4"n"+11)="a"^27`
Comparing both sides, we get
`4"n"+11=27`
`⇒4"n"=27-11`
`⇒"n"=16/4=4`
shaalaa.com
More About Exponents
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Compute:
`1^8xx3^0xx5^3xx2^2`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`(27/64)^(-2/3)`
Evaluate:
`(-5)^0`
Evaluate:
`8^0+4^0+2^0`
Evaluate:
`(4"x")^0`
Simplify:
`(36"x"^2)^(1/2)`
Simplify:
`(27"x"^-3"y"^6)^(2/3)`
Prove that:
`1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a"))=1`
Find the value of n, when:
`12^-5xx12^(2"n"+1)=12^13÷12^7`
