Advertisements
Advertisements
Question
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
Advertisements
Solution
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
`("a"^(2"n"-3)xxa^(2"n"+2))/"a"^-12="a"^9÷"a"^-18`
`("a"^(2"n"-3)xx2^(2"n"+2))/"a"^-12="a"^9/"a"^-18`
`"a"^(2"n"-3+2"n"+2-(-12)="a"^9-(-18))`
`"a"^(4"n"+11)="a"^27`
Comparing both sides, we get
`4"n"+11=27`
`⇒4"n"=27-11`
`⇒"n"=16/4=4`
APPEARS IN
RELATED QUESTIONS
Compute:
`(2/3)^(-4)xx(27/8)^-2`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Simplify:
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
Evaluate:
`(8+4+2)^0`
Evaluate:
`(4"x")^0`
Evaluate:
`[(10^3)^0]^5`
Simplify:
`"x"^10"y"^6÷"x"^3"y"^-2`
Evaluate:
`("a"^(2"n"+1)xx"a"^((2"n"+1)(2"n"-1)))/("a"^("n"(4"n"-1))xx("a"^2)^(2"n"+3)`
Prove that:
`1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a"))=1`
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
