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प्रश्न
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
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उत्तर
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
`("a"^(2"n"-3)xxa^(2"n"+2))/"a"^-12="a"^9÷"a"^-18`
`("a"^(2"n"-3)xx2^(2"n"+2))/"a"^-12="a"^9/"a"^-18`
`"a"^(2"n"-3+2"n"+2-(-12)="a"^9-(-18))`
`"a"^(4"n"+11)="a"^27`
Comparing both sides, we get
`4"n"+11=27`
`⇒4"n"=27-11`
`⇒"n"=16/4=4`
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संबंधित प्रश्न
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`(56/28)^0÷(2/5)^3xx16/25`
Compute:
`(-5)^4xx(-5)^6÷(-5)^9`
Compute:
`(27)^(2/3)÷(81/16)^(-1/4)`
Evaluate:
`(-5)^0`
Evaluate:
`(4"x")^0`
Evaluate:
`(7"x"^0)^2`
Simplify:
`15"y"^8÷3"y"^3`
Simplify and express as positive indice:
(xy)(m-n).(yz)(n-l).(zx)(l-m)
Show that:
`(("x"^"a")/"x"^(-"b"))^("a"-"b").(("x"^"b")/"x"^(-"c"))^("b"-"c").(("x"^"c")/("x"^(-"a")))^("c"-"a")=1`
