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प्रश्न
Find the value of n, when:
`12^-5xx12^(2"n"+1)=12^13÷12^7`
योग
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उत्तर
`12^-5xx12^(2"n"+1)=12^13÷12^7`
`12^(-5+2"n"+1)=12^13/12^7`
`12^(2"n"-4)=12^(13-7)`
`12^(2"n"-4)=12^6`
Comparing both sides,we get
`2"n"-4=6`
`⇒2"n"=6+4`
`⇒2"n"=10`
`⇒"n"=5`
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